Hi,
I have learn (or I think so) the way capacitors 'mod' the sound.
Usually we use .22 x strat .47 x kinda of les paul. More voltage of capacitors gives a smoother effects but at the same time are bigger.

ok.

But what are the difference in use 250k or 500k pot both x volume or tone or a mix of it?
In what way they influence the sound, volume, or what else they do?
at the same time usually strat pots are 250k, but many use 500k. so why and what changes?

thank you very much to who will explain to me

Common caps for tone control circuits are .01mfd, .022mfd, .033mfd, and .047mfd.

Big difference.

Arjay

_________________
"Here's why reliability is job one: A great sounding amp that breaks down goes from being a favorite piece of gear to a useless piece of crap in less time than it takes to read this sentence." -- BRUCE ZINKY

Hi diSTRATto,

If you use the 500K pots with single coils, the tone is maybe slightly different, but the tone isn't affected so much as the change in how far you have to rotate the pot before you start to get volume. Typically, the 500K pots are a better match for humbucker pickups, while the 250K are a better match for the single coil pickups, although there are really no rules for which to use, so you can experiment and see which you like.

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I'll explain this in as non-technical terms as I can.

The larger the cap (not physical size, the microfarads), the more it attenuates high frequency (treble).

The higher the k ohms of the pot (vol), more of the signal from the pickups go directly to the amp. Complicating this is what the impedance (k ohms) is of each pickup. The pickups also have an inductance characteristic. The impedance (R), inductance (L) and tone cap (C) all have an effect on the signal going to the amp. There is some cap effect even when the tone is turned all the way up. Having a tone bypass switch eliminates this. (similar to Eddie Van Halen's frankenstrat). Having a volume bypass switch (strat deluxe), eliminates the volume pot.

There's a ton of control options for different tone. As mentioned, a 500k pot will make the guitar sound a bit brighter.....this is true at the louder volumes (once you get above 250k).

Remember also that most pots are audio taper, meaning that it increases logrithmcaly as you turn it, so if you buy a replacement, check the old one first to see if it's log or linear.

A push/pull pot is another great way to add options.

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2002 mim Telecaster
Jimmie Vaughan Stratocaster
Mexican HSS Stratocaster
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1 wife (uh....no comment)

thanks jack, very great explanation.

talking about pot, sure they often are log, but don't you think will be better a linear ??
(that as the word, will increase or decrease volume linear)

The log pots actually sound as if they are linear. A linear pot won't sound linear, it will sound like an odd tapered pot.

_________________
---> "The amp should be SWITCHED OFF AND UNPLUGGED before you do this!" <---

Por favor, disculpe mi español, no se llega a la práctica con mucha frecuencia.

The ear responds logarithmically to increases in sound pressure. each doubling in signal is perceived as an equal step in volume so a linear pot won't produce a smooth sounding sweep. if you used a linear pot, you would have to turn the knob twice as far from 2-
3 to get the same increase in 'loudness' as you would turn it from 1-2. 3-4 would need twice as much of a turn as 2-3, and so on. So assuming a log pot and an audio taper pot have the same starting point (zero,) and the same end,(equivalent to 10 on your pot,)
a linear pot would change a ton on the tiniest tweaks all at the the start of the sweep from zero, and as you get toward the loudest part the changes would be uber small.
The audio taper pot divides this sweep into ten equal segments of the sweep. the linear pot would essentially be broken into 511 segments. A change in volume = 1-2 on the audio taper pot is 1/1oth of the rotation of the pot. On a linear pot it is 1/511th, I don't think I am that dextrous. then on the other end on our pots the same size sweep (of 1/10th of the pots rotation,) moves us from 9 -10, but on a linear pot you would use 256 of those segments, so that's just over half of the sweep of the pot.

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